• If there was a tube with water sealed into it, hanging vertically and you released a small ball into the tube, would it float to the top?

    Best answer: Water is incompressible. If you don't let some water out, or if the tube is not flexible, then it is impossible to put anything else in. Assuming that you have released sufficient water so that the ball actually fits into the tube then it displaces water. Archimedes pointed out that for the ball to go up... show more
    Best answer: Water is incompressible. If you don't let some water out, or if the tube is not flexible, then it is impossible to put anything else in.

    Assuming that you have released sufficient water so that the ball actually fits into the tube then it displaces water.
    Archimedes pointed out that for the ball to go up water must go down. Easy.
    Which means that if the weight of the ball is LESS than the weight of the water that it displaces then the ball goes up and the water goes down.

    Of course if the DENSITY of the ball is greater than that of the water then the ball goes down and the water goes up.
    This is called "siinking".

    All of this happens whether in a sealed tube or in the open ocean.
    7 answers · 7 days ago
  • Would you use a teleportation device that destroyed you and reassembled you?

    Would you use a teleportation device that instantaneously destroyed you in one location and reassembled you perfectly (with different atomic particles) in another location?
    Would you use a teleportation device that instantaneously destroyed you in one location and reassembled you perfectly (with different atomic particles) in another location?
    5 answers · 5 days ago
  • Help with physics please?

    A car starts from rest, then accelerates at 1.20 m/s^2 for 7.00 s. It hits the breaks, slowing t a stop at a rate of -4.25 m/s^2. What is the total distance traveled?
    A car starts from rest, then accelerates at 1.20 m/s^2 for 7.00 s. It hits the breaks, slowing t a stop at a rate of -4.25 m/s^2. What is the total distance traveled?
    5 answers · 6 days ago
  • Please help!?

    A 93.4 kg cross country skier on snow has mu = 0.0995. With how much force must he push to accelerate at 0.550 m/s^2?
    A 93.4 kg cross country skier on snow has mu = 0.0995. With how much force must he push to accelerate at 0.550 m/s^2?
    4 answers · 6 days ago
  • What would happen to a black hole if there were no space around it?

    Say all the black holes merged together near the end of the universe and space-Time fell back into it through some energy loss event, what would happen to the black hole?
    Say all the black holes merged together near the end of the universe and space-Time fell back into it through some energy loss event, what would happen to the black hole?
    20 answers · 2 weeks ago
  • Physics 11 question!! pls help (Kinematics)?

    Best answer: You need to set your origin and positive direction and then stick with it throughout the problem You state that the positive direction is toward the hole. It makes sense that the origin should be at the initial position of the golf ball as it starts rolling. In this reference frame, the initial velocity is... show more
    Best answer: You need to set your origin and positive direction and then stick with it throughout the problem

    You state that the positive direction is toward the hole.
    It makes sense that the origin should be at the initial position of the golf ball as it starts rolling.

    In this reference frame, the initial velocity is positive and the acceleration is towards the origin or in the negative direction

    v = u + at
    v = 2.0 + (-0.5)(2.0)
    v = 1.0 m/s

    I hope this helps.
    Please remember to vote a "Best Answer" from among your results. It s good karma as it helps keep the exchange in balance.
    5 answers · 1 week ago
  • Please help me in physics!?

    Best answer: This problem does not say the car’s final velocity. To solve this problem, I will have to assume that the car’s final velocity is not 0 m/s. Since we know the initial velocity, distance, and the acceleration, we can use the following equation to determine the car’s final velocity. vf^2 = vi^2 + 2 * a * d vf^2 =... show more
    Best answer: This problem does not say the car’s final velocity. To solve this problem, I will have to assume that the car’s final velocity is not 0 m/s. Since we know the initial velocity, distance, and the acceleration, we can use the following equation to determine the car’s final velocity.

    vf^2 = vi^2 + 2 * a * d
    vf^2 = 25.5^2 + 2 * -2.40 * 88.4
    vf = √210.72

    The final velocity is approximately 14.5 m/s. Let’s use the following equation to determine the time for car’s velocity to decrease from 25.5 m/s to approximately 14.5 m/s with an acceleration of -2.40 m/s.

    vf = vi + a * t
    √210.72 = 25.5 + -2.40 * t
    t = (25.5 – √210.72) ÷ 2.40

    The time is approximately 4.6 seconds. Let’s assume the final velocity is 0 m/s. Let’s use the equation above to determine the time.

    0 = 25.5 + -2.40 * t
    t = 25.5 ÷ 2.40 = 10.625 seconds

    Let’s use the equation above to determine the total distance.

    d = ½ * (vi + vf) * t, vf = 0
    d = ½ * 25.5 * 10.625 = 134.46875 meters

    Since this is more than 88.4 meters, my assumption that the final velocity was not 0 m/s was correct. I hope this is helpful for you.
    4 answers · 7 days ago
  • Can someone explain to me the quantum mechanics analogy in the photo from my textbook that I attached to this question?

    Can someone explain to me the quantum mechanics analogy in the photo from my textbook that I attached to this question?

    Best answer: The analogy is a poor one.

    A fan is 'classical': you can find the position and speed of a blade as accurately as you want. You are only limited by the precision of your equipment.

    The same is *not* true of an electron in an atom (as expressed byHeisenberg’s uncertainty principle).
    Best answer: The analogy is a poor one.

    A fan is 'classical': you can find the position and speed of a blade as accurately as you want. You are only limited by the precision of your equipment.

    The same is *not* true of an electron in an atom (as expressed byHeisenberg’s uncertainty principle).
    8 answers · 1 week ago
  • What is its orbital period in years?

    An asteroid orbits the sun (mass = 1.99 x 10^30 kg) at a distance of 3.90 x 10^11 m. What is its orbital period (in years?)
    An asteroid orbits the sun (mass = 1.99 x 10^30 kg) at a distance of 3.90 x 10^11 m. What is its orbital period (in years?)
    3 answers · 1 week ago
  • If the big bang was created out of two particles smaller than atoms, then how come the LHC is safe?

    Best answer: The big bang was not created by two particles. It was the creation and expansion of spacetime itself.
    The LHC does not smash particles with energy higher than cosmic rays that hit the atmosphere all the time. The LHC just collides particles in a controlled way near detecters used to analyze them.
    Best answer: The big bang was not created by two particles. It was the creation and expansion of spacetime itself.
    The LHC does not smash particles with energy higher than cosmic rays that hit the atmosphere all the time. The LHC just collides particles in a controlled way near detecters used to analyze them.
    11 answers · 2 weeks ago
  • Help with velocity problem? I have done it 3 times now, and the computer still says I'm wrong?

    Near the surface of the earth, the acceleration of a falling body due to gravity is 32 feet per second per second, provided that air resistance is neglected. If an object is thrown upward from and initial height of 3000 feet with a velocity of 100 feet per second, find its velocity and height 6 seconds later.
    Near the surface of the earth, the acceleration of a falling body due to gravity is 32 feet per second per second, provided that air resistance is neglected. If an object is thrown upward from and initial height of 3000 feet with a velocity of 100 feet per second, find its velocity and height 6 seconds later.
    5 answers · 1 week ago
  • HELP PLEASE?

    Best answer: specific heat ca of ethyl alcohol is worth 2432 joule/kg/°C
    specific heat cw of l water is worth 4186 joule/kg/°C
    (ma*ca*Ta+mw*cw*Tw) = (ma*ca+mw*cw)*Te
    Te = (ma*ca*Ta+mw*cw*Tw)/(ma*ca+mw*cw)
    since ma = mw , they can be omitted
    Te = (2432*33+4186*22)/(2432+4186) = 26.0 °C
    Best answer: specific heat ca of ethyl alcohol is worth 2432 joule/kg/°C
    specific heat cw of l water is worth 4186 joule/kg/°C
    (ma*ca*Ta+mw*cw*Tw) = (ma*ca+mw*cw)*Te
    Te = (ma*ca*Ta+mw*cw*Tw)/(ma*ca+mw*cw)
    since ma = mw , they can be omitted
    Te = (2432*33+4186*22)/(2432+4186) = 26.0 °C
    5 answers · 2 weeks ago
  • Deriving the Speed of Light?

    Best answer: Electromagnetic wave equation is a source free equation. It propagates independently of charge and current. Of course that makes it a vacuum solution. It’s easiest to see that with Maxwell equations in differential form.
    Best answer: Electromagnetic wave equation is a source free equation. It propagates independently of charge and current. Of course that makes it a vacuum solution. It’s easiest to see that with Maxwell equations in differential form.
    4 answers · 1 week ago
  • Help with physics question?

    Best answer: At (0, -R) the tangential acceleration is 3i, therefore we can assume that the tangential acceleration always has a value of 3 m/s² At that point, the centripetal acceleration is 4j, so we can figure the velocity at that point a = v²/r v = √(ar) v = √(4(25)) v = 10 m/s this means the particle was last at rest 10... show more
    Best answer: At (0, -R) the tangential acceleration is 3i, therefore we can assume that the tangential acceleration always has a value of 3 m/s²
    At that point, the centripetal acceleration is 4j, so we can figure the velocity at that point

    a = v²/r
    v = √(ar)
    v = √(4(25))
    v = 10 m/s

    this means the particle was last at rest 10 m/s / 3 m/s² = 3⅓ seconds ago.

    The arc length traveled in 3⅓ seconds is

    d = ½(3)(3⅓)²
    d = 16⅔ m

    which is far less than the arc length of 1.5πR (about 118 m) so the particle has not yet traveled in a CCW direction through (R,0) therefore, reaching that point is to occur sometime in the future.

    The arc length distance from (0, -R) to (R, 0) is

    d = ½πR
    d = 12.5π or about 39.27 m

    analyzing the tangential velocity

    v² = u² + 2as

    v² = 10² + 2(3)(12.5π)
    v² = 335.619...

    so the acceleration at (R, 0) has centripetal acceleration in the negative x direction and tangential acceleration in the positive y direction

    a = -(v²/r)i + 3j
    a = -(335.619/25)i + 3j
    a = -13.425i + 3j

    I hope this helps.
    Please remember to vote a "Best Answer" from among your results. It s good karma as it helps keep the exchange in balance.
    4 answers · 1 week ago
  • A plane is flying east at 115 m/s.?

    A plane is flying east at 115 m/s. The wind accelerates it at 2.88 m/s^2 directly northeast. After 25.0 s, what is the direction of the velocity of the plane?
    A plane is flying east at 115 m/s. The wind accelerates it at 2.88 m/s^2 directly northeast. After 25.0 s, what is the direction of the velocity of the plane?
    3 answers · 1 week ago
  • Physics, Please help! Thank You in advance!!?

    A vector has an x-component of 6.15 m and a y-component of -3.88 m. Find the magnitude of the vector.
    A vector has an x-component of 6.15 m and a y-component of -3.88 m. Find the magnitude of the vector.
    4 answers · 1 week ago
  • Why doesn't gravity pull a person's belly down? Why does it stick out instead?

    Best answer: If you see someone with a large belly and a tight belt, you will see some the belly hanging over the belt. The muscles in that area prevent the belly from falling to the ground
    Best answer: If you see someone with a large belly and a tight belt, you will see some the belly hanging over the belt. The muscles in that area prevent the belly from falling to the ground
    6 answers · 2 weeks ago
  • Is it possible to go to a fantasy world?

    I know this sounds weird, but I have always wanted to go to fantasy world where I could do anything. I have come to accept that the world we live in will always be full of suffering, and I know that I will never be able to reach or explore my dreams. I am a bit of a weird guy, and I always struggle to interact with... show more
    I know this sounds weird, but I have always wanted to go to fantasy world where I could do anything. I have come to accept that the world we live in will always be full of suffering, and I know that I will never be able to reach or explore my dreams. I am a bit of a weird guy, and I always struggle to interact with people. I find this hard to explain, but I don't think like normal people. My thought process is different and I often do things that I can't explain. I am also very paranoid and depressed most of the time. The only thing that keeps me from becoming even more depressed or paranoid is my religion. Its like a coping mechanism for me, telling me that everything will become alright, as there is a heaven and that God is protecting and watching over you. I also watch anime and read manga, which I feel has fueled my desire to go to a fantasy world. Even as child I felt that I wanted to go to these wonderful places where I could be someone important; where I could have power; where I could have someone beautiful to love me. I know people tell me there is a heaven, but I feel that in that heaven I wouldn't really be able to explore my dreams and desires. I have seen things on youtube, where they say that subliminals can send you to another world, or if you wish for it using "magic" it could happen. The truth is I don't know if any of these work, and I am scared they may lead to something demonic. Please could you tell me if there is a way, and whether it is safe to do.
    4 answers · 1 week ago
  • I DONT UNDERSTAND?

    Best answer: Efficiency = work output / energy input = (702 J) / (5280 J) = 0.133
    (There will be no unit because J (joule) in numerator and J in denominator will cancel each other)

    Efficiency of 0.133 = 13.3 % (simply multiply by 100)
    Best answer: Efficiency = work output / energy input = (702 J) / (5280 J) = 0.133
    (There will be no unit because J (joule) in numerator and J in denominator will cancel each other)

    Efficiency of 0.133 = 13.3 % (simply multiply by 100)
    4 answers · 1 week ago
  • Physics help, please!!?

    Best answer: As the car decelerates, d = ½ * (vi + vf) * t
    d = ½ * (28.5 + 15.0) * 2.37 = 51.5475 meters

    At a constant speed, d = 15.0 * 8.25 = 123.75 meters
    Total distance = 51.5475 + 123.75 = 175.2975 meters
    Rounded to three significant digits, this is 175 meters.
    Best answer: As the car decelerates, d = ½ * (vi + vf) * t
    d = ½ * (28.5 + 15.0) * 2.37 = 51.5475 meters

    At a constant speed, d = 15.0 * 8.25 = 123.75 meters
    Total distance = 51.5475 + 123.75 = 175.2975 meters
    Rounded to three significant digits, this is 175 meters.
    4 answers · 1 week ago