# Emperical Formula for Vanadium oxide?

Vanadium oxide is used as an industrial catalyst. The percent composition of this oxide is 56.0% vanadium and 44.0% oxygen. Determine the emperical formula for vanadium oxide.

### 4 Answers

- Flying DragonLv 71 decade agoFavourite answer
To do these, you need to get weight % into something proportional to mole %. Just divide the weight % of each component by it atomic weight and you will get numbers that are proportional to relative numbers of V & O atoms:

56%/50.94 = 1.099

44%/16.00 = 2.75

Now, divide both numbers by the smallest one to try to get them into whole numbers

1.099/1.099 = 1.00

2.75/1.099 = 2.50

Since we can't have a half of an atom in the formula, we will multiply everything by 2 to get both of them into whole numbers.

Thus, the formula becomes V2O5.

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- dampierLv 44 years ago
Vanadium Oxide

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- karLv 44 years ago
V2O5. it is regularly referred to as "vanadium pentoxide." it is used as a catalyst in chemical reactions. case in point, it is widespread (as a action picture on a ceramic substrate) via fact the catalyst to transform SO2 to SO3, interior the manufacture of H2SO4.

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- Anonymous1 decade ago
Vee O five

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