# Determine the distance travelled by the mass while it is accelerating upwards.?

I don't know how to answer this physics question, basically there is a graph, velocity against time graph. it increases rapidly until 0.7 seconds (2.1 m/s)and starts to level off after that and is a straight line (2.5m/s) after 1 second. It sarts to decrease by levelling off a bit from 3.9 s to 4.2 s (2.1... show more I don't know how to answer this physics question, basically there is a graph, velocity against time graph.

it increases rapidly until 0.7 seconds (2.1 m/s)and starts to level off after that and is a straight line (2.5m/s) after 1 second. It sarts to decrease by levelling off a bit from 3.9 s to 4.2 s (2.1 m/s). And decreases in a steep line rapidly as well to 4.7 seconds to 0meterpersecond.

My question here is what are the answers for these question and why is that ( so please a bit more explanation why certain figures are used would help)
(a) Determine
(i) the initial uniform acceleration of the mass
(ii) the distance travelled by the mass while it is accelerating upwards
the answers are supposed to be:
(a) (i) gradient = = 3.0 ms–2 (1)

(ii) distance is area under graph (to t = 0.1 s)
or × 0.7 × 2.1 0.3 (1) = 1.4(2) m (1)

but why is that, because I don't get the same solution with my calculater.

Update: sorry I meant the asnwers are:
ii) 0.7 x 2.1 x ((2.1+2.5)/2) 0.3 = 1.4(2) m (1)
Update 2: sorry I meant the asnwers are:
ii) 0.7 x 2.1 x ((2.1+2.5)/2) 0.3 = 1.4(2) m (1)
Update 3: sorry I meant the asnwers are:
ii) 0.7 x 2.1 x ((2.1+2.5)/2) 0.3 = 1.4(2) m (1)
Update 4: sorry I meant the asnwers are: