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Two forces, of magnitudes F1 = 90.0 N and F2 = 45.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position xi = -6.00 cm . At some later time, the block has moved to the right, and its center is at a new... show more Two forces, of magnitudes F1 = 90.0 N and F2 = 45.0 N , act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position xi = -6.00 cm . At some later time, the block has moved to the right, and its center is at a new position, xf = 5.00 cm .
Part A
Find the work W1 done on the block by the force of magnitude F1 = 90.0 N as the block moves from xi = -6.00 cm to xf = 5.00 cm .
Express your answer numerically, in joules.
W1 = J

Part B

Find the work W2 done by the force of magnitude F2 = 45.0 N as the block moves from xi = -6.00 cm to xf = 5.00 cm .
Express your answer numerically, in joules.

W2 =J
Part C

What is the net work Wnet done on the block by the two forces?
Express your answer numerically, in joules.
Wnet = J

Part D

Determine the changeKf−Ki in the kinetic energy of the block as it moves from xi = -6.00 cm to xf = 5.00 cm .
Express your answer numerically, in joules.
Kf−Ki = J
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