### 6 Answers

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- ComoLv 72 years ago
y = (2 - x) x^(1/2)

dy/dx = (-1) x^(1/2) + (1/2) x^(-1/2) (2 - x)

dy/dx = (-1/2) x^(-1/2) [ 2 x - (2 - x) ]

dy/dx = [ 3x - 2 ] / [ 2 x^(1/2) ]

- Iggy RockoLv 72 years ago
y = (2 - x)√x

y = 2√x - x^(3/2)

dy/dx = 2 * 1/2 * x^(-1/2) - 3/2 * x^(1/2)

dy/dx = 1/x^(1/2) - 3x^(1/2)/2

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