Anonymous
Anonymous asked in Science & MathematicsAstronomy & Space · 9 months ago

# Suppose the Moon is 381 thousand km from Earth, and its orbital period is 27.3 days. What is the Moon's speed in km/hr for this orbit?

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• Anonymous
8 months ago

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• 9 months ago

r = radius of the Moon's orbit = 381,000 km

π = 3.141592654

C = circumference of the Moon's orbit = to be determined

C = 2πr

C = 2 x 3.141593 x 381,000 km

C = 2,393,894 km

1 day = 24 hr

t = elapsed time = 27.3 days = 27.3 dy x 24 hr/dy = 655.2 hr

S = orbital speed of the Moon = to be determined

S = C/t

S = 2,393,894 km / 655.2 hr

S = 3,654 km/hr

• 9 months ago

2093 feet per second. Have fun converting

• 9 months ago

So, the radius of the moon's orbit is 381,000 km. To find the distance it travels:

C = 2 x pi x r

C = 2 x 3.141592 x 381,000km

C = 2,393,893km

Now, divide this by 27.3 days, then divide that by 24 to get km/hour.

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