Consider the evaporation of methanol at 25.0∘C: CH3OH(l)→CH3OH(g).?

PCH3OH=159.0 mmHg

Express the free energy change in kilojoules to one decimal place.

PCH3OH=104.0 mmHg

Express the free energy change in kilojoules to one decimal place.

PCH3OH=12.00 mmHg

Express the free energy change in kilojoules to one decimal place.

1 Answer

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  • 1 year ago

    Just use the equation:

    Delta Go = - RT ln PCH3OH where the pressure is expressed in atm, and T in Kelven. R = 8.314 J/molK

    For the first one,

    159.0 mm Hg / 760 mmHg/atm = 0.209 atm

    Delta G = - 8.314 J/molK (298 K) ln 0.209

    Delta G = +3.88X10^3 J/mol = +3.88 kJ/mol

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