A force of 303.0 N is used to push a 170 kg mass 30.0 m horizontally in 3.00 s.?
(a) Calculate the work done on the mass.
(b) Calculate the power developed.
- MyRankLv 61 year ago
Force (F) = 303 N
Mass (m) = 170 kg
Distance (d) = 30 m
Time (t) = 3 sec
a) Work done (W) =?
Work done (W) = Force x distance
= 303 N x 30 m
= 9090 Nm
≈ 9090 J
∴ Work done (W) = 9090 J
b) Power (P) =?
Power (P) = Work done (W)/ Time (t)
= 9090 J/ 3 sec
= 3030 Watts
∴ Power (P) = 3030 Watts.Source(s): http://myrank.co.in/
- LônLv 71 year ago
The mass is irrelevant in this equation as friction is not mentioned so all the force goes to moving the mass.
Work done = force x distance moved = 303 x 30 = 9090 J or 9.09 kJ
Power = work done/time taken = 9090/3 = 3030W or 3.03 kW