A force of 303.0 N is used to push a 170 kg mass 30.0 m horizontally in 3.00 s.?

(a) Calculate the work done on the mass.

kJ

(b) Calculate the power developed.

kW

2 Answers

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  • MyRank
    Lv 6
    1 year ago

    Given,

    Force (F) = 303 N

    Mass (m) = 170 kg

    Distance (d) = 30 m

    Time (t) = 3 sec

    a) Work done (W) =?

    Work done (W) = Force x distance

    = 303 N x 30 m

    = 9090 Nm

    ≈ 9090 J

    ∴ Work done (W) = 9090 J

    b) Power (P) =?

    Power (P) = Work done (W)/ Time (t)

    = 9090 J/ 3 sec

    = 3030 Watts

    ∴ Power (P) = 3030 Watts.

  • Lôn
    Lv 7
    1 year ago

    The mass is irrelevant in this equation as friction is not mentioned so all the force goes to moving the mass.

    Work done = force x distance moved = 303 x 30 = 9090 J or 9.09 kJ

    Power = work done/time taken = 9090/3 = 3030W or 3.03 kW

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