# A force of 303.0 N is used to push a 170 kg mass 30.0 m horizontally in 3.00 s.?

(a) Calculate the work done on the mass.

kJ

(b) Calculate the power developed.

kW

### 2 Answers

Relevance

- MyRankLv 61 year ago
Given,

Force (F) = 303 N

Mass (m) = 170 kg

Distance (d) = 30 m

Time (t) = 3 sec

a) Work done (W) =?

Work done (W) = Force x distance

= 303 N x 30 m

= 9090 Nm

≈ 9090 J

∴ Work done (W) = 9090 J

b) Power (P) =?

Power (P) = Work done (W)/ Time (t)

= 9090 J/ 3 sec

= 3030 Watts

∴ Power (P) = 3030 Watts.

Source(s): http://myrank.co.in/ - LônLv 71 year ago
The mass is irrelevant in this equation as friction is not mentioned so all the force goes to moving the mass.

Work done = force x distance moved = 303 x 30 = 9090 J or 9.09 kJ

Power = work done/time taken = 9090/3 = 3030W or 3.03 kW

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