Leslie asked in Science & MathematicsPhysics · 1 year ago

# lawn roller pushed across a lawn by a force of 103 N along the direction of the handle, which is 22.5° above the?

horizontal. If you develop 65.3 W of power for 90.0 s, what distance is the roller pushed?

Relevance
• oubaas
Lv 7
1 year ago

Effective force Fe = F*cos 22.5 = 103*0.924 = 95.16 N

power P = Fe*V

V = P/Fe = 65.3/95.16 = 0.686 m/sec

distance d = V*t = 0.686*90 = 61.76 m

• 1 year ago

force.

Fh = 103 * cos 22.5

This is approximately 95.2 N. Let’s use the following equation to determine work.

Power = Work ÷ time

65.3 = Work ÷90

Work = 5,877 N* m

Work = Force * distance

5,877 = 103 * cos 22.5 * distance

Distance = 5,877 ÷ 103 * cos 22.5

The distance is approximately 61.7 meters. I hope this is helpful for you.