lawn roller pushed across a lawn by a force of 103 N along the direction of the handle, which is 22.5° above the?

horizontal. If you develop 65.3 W of power for 90.0 s, what distance is the roller pushed?

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  • oubaas
    Lv 7
    1 year ago

    Effective force Fe = F*cos 22.5 = 103*0.924 = 95.16 N

    power P = Fe*V

    V = P/Fe = 65.3/95.16 = 0.686 m/sec

    distance d = V*t = 0.686*90 = 61.76 m

  • 1 year ago

    force.

    Fh = 103 * cos 22.5

    This is approximately 95.2 N. Let’s use the following equation to determine work.

    Power = Work ÷ time

    65.3 = Work ÷90

    Work = 5,877 N* m

    Work = Force * distance

    5,877 = 103 * cos 22.5 * distance

    Distance = 5,877 ÷ 103 * cos 22.5

    The distance is approximately 61.7 meters. I hope this is helpful for you.

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