athlete lifts a barbell three times as high as another. What is the ratio of changes in potential energy in the two lifts?

2 Answers

  • 1 year ago

    I cannot understand why you would ask this question.

    However if the gain in potential energy = mgh

    then to do it formally

    p2/p1 = ( mgh2)/ mgh1)

    if both m and g are kept the same then

    p2/p1 = h2/h1 = 3/1 = 3

  • alex
    Lv 7
    1 year ago


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