what is the oxidation state of Fe in Na[HFE(CO)4)] is it 0?

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  • 1 year ago

    The H atom is removed as H^- because the electronegativity of H is greater than the TM. [1] TM cmplxs with H ligands are therefore called hydrides. (It is not an indication of their chemistry.) Hence:

    [Fe(CO)4(H]^-1

    [Fe] - 4x0 (four CO ligands) -1 (H^-) = -1

    Hence Fe(0)

    [1] https://en.wikipedia.org/wiki/Electronegativities_...

  • 1 year ago

    Oxidation state of Fe

    Na[HFe(CO)4]..... Na+ has an oxidation state of +1. The [HFe(CO)4]- ion is -1.

    The name is tetracarbonylhydroferrate(1-). Iron can be assigned an oxidation state of -1. CO is neutral and if hydrogen is assigned an oxidation state of 0, then iron has an oxidation state of -1.

    Or we can say that CO is neutral and hydrogen is assigned an oxidation state of +1, and iron has an oxidation state of -2.

    Or we can say that iron has an oxidation state of zero, and hydrogen has an oxidation state of -1 (making in a "hydride").

    One important take-away is that the oxidation state is an assigned number. It is not a number which has some physical significance, nor is it an actual electronic charge. Oxidation states are good for doing some "chemical bookkeeping."

  • david
    Lv 7
    1 year ago

    6+

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