what is the oxidation state of Fe in Na[HFE(CO)4)] is it 0?
- GeorgeSiO2Lv 71 year ago
The H atom is removed as H^- because the electronegativity of H is greater than the TM.  TM cmplxs with H ligands are therefore called hydrides. (It is not an indication of their chemistry.) Hence:
[Fe] - 4x0 (four CO ligands) -1 (H^-) = -1
- pisgahchemistLv 71 year ago
Oxidation state of Fe
Na[HFe(CO)4]..... Na+ has an oxidation state of +1. The [HFe(CO)4]- ion is -1.
The name is tetracarbonylhydroferrate(1-). Iron can be assigned an oxidation state of -1. CO is neutral and if hydrogen is assigned an oxidation state of 0, then iron has an oxidation state of -1.
Or we can say that CO is neutral and hydrogen is assigned an oxidation state of +1, and iron has an oxidation state of -2.
Or we can say that iron has an oxidation state of zero, and hydrogen has an oxidation state of -1 (making in a "hydride").
One important take-away is that the oxidation state is an assigned number. It is not a number which has some physical significance, nor is it an actual electronic charge. Oxidation states are good for doing some "chemical bookkeeping."
- davidLv 71 year ago