CHEMISTRY HW HELP!?
What would the product be for this reactant? Also, explain how you got your answer please.
- DrBob1Lv 712 months agoFavourite answer
The expected product is 3,3-dimethyl-1-butanol. This is unusual since it is the "AntiMarkovnikov" product of alkene hydration. We are familiar with the ionization of water to yield H+ and OH- ions. The H and OH should be switched.
But here, note the reactant adds B and H to the double bond; the Boron atom is replaced by Oxygen. Analysis of the charges of the reactants show that truly we add OH+ and H-. Markovnikov RULES!!!