Anonymous asked in Science & MathematicsChemistry · 12 months ago


What would the product be for this reactant? Also, explain how you got your answer please.

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1 Answer

  • DrBob1
    Lv 7
    12 months ago
    Favourite answer

    The expected product is 3,3-dimethyl-1-butanol. This is unusual since it is the "AntiMarkovnikov" product of alkene hydration. We are familiar with the ionization of water to yield H+ and OH- ions. The H and OH should be switched.

    But here, note the reactant adds B and H to the double bond; the Boron atom is replaced by Oxygen. Analysis of the charges of the reactants show that truly we add OH+ and H-. Markovnikov RULES!!!

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