### 3 Answers

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- TomVLv 71 year ago
Obviously you are on a 4.0 system. We used a 3.0 system at my university. A = 3, B = 2, C = 1, D & F = 0 The only difference between a D and an F, was an F in a required course necessitated retaking the course. D's did not.

In a 4.0 system, A = 4, B = 3

1 A + 1 B = 7/2 = 3.5 GPA

1 A + 2 B = 10/3 = 3.33

1 A + 3 B = 13/4 = 3.25

So, if you have nothing but A's and B's, then for every 3 B's, you must have 1 A to achieve a 3.25 GPA.

- 1 year ago
3 Bs to every A.

3B, 1A

6B , 2A

9B , 3A

12B , 4A

and so on

(3b + 4a) / (b + a) = 3.25

(3b + 4a) / (b + a) = 13/4

4 * (3b + 4a) = 13 * (b + a)

12b + 16a = 13b + 13a

16a - 13a = 13b - 12b

3a = b

So if you have 1 A, then you need 3 Bs

If you have 100 As, then you need 300 Bs

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