# Calculate the amount of heat which must be removed from 400 kg fish.....?

Calculate the amount of heat which must be removed from 400 kg fish, if it enters a freezer room at 15 degrees *c and is pulled down to -18 deg Celsius.
Must show all working.
Fomula:
Q=mc^t
Q=mL
Specific heat of fish above freezing = 1.95 kJ/kgk
Specific heat of fish below freezing = 1.10 kJ/kgk
Latent heat-...
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Calculate the amount of heat which must be removed from 400 kg fish, if it enters a freezer room at 15 degrees *c and is pulled down to -18 deg Celsius.

Must show all working.

Fomula:

Q=mc^t

Q=mL

Specific heat of fish above freezing = 1.95 kJ/kgk

Specific heat of fish below freezing = 1.10 kJ/kgk

Latent heat- 110 kJ/kg

Must show all working.

Fomula:

Q=mc^t

Q=mL

Specific heat of fish above freezing = 1.95 kJ/kgk

Specific heat of fish below freezing = 1.10 kJ/kgk

Latent heat- 110 kJ/kg

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