Anonymous asked in Science & MathematicsChemistry · 6 months ago

Can someone check my answers? a. Ba2+, Mn2+ are present b. Mn2+ is present c. Mn2+ is present?

Attachment image

2 Answers

  • 6 months ago
    Favorite Answer

    So, your final answer would be that Mn2+ is the only one of these ions present in the solution. For each part, it would be better to say:

    a. Hg22+ is not present

    b. Ba2+ is not present

    c. Mn2+ is present

    • Log in to reply to the answers
  • 6 months ago

    Ion analysis.....

    BaCl2 and MnCl2 are both soluble.

    MnSO4 is soluble.

    Hg2Cl2(s), Hg2SO4(s), and BaSO4(s) are insoluble

    Hg(s) and HgO(s) form where one would expect Hg2(OH)2

    Ba(OH)2(s) is slightly soluble, a precipitate will depend on the ion concentration

    Mn(OH)2(s) is insoluble

    Hg2^2+ + 2Cl- --> Hg2Cl2(s)

    Ba2+ + Cl- --> no reaction

    Mn2+ + Cl- --> no reaction

    If there is no precipitate when Cl- added, there is no Hg2^2+ present.

    Ba2+ + SO4^2- --> BaSO4(s)

    Mn2+ + SO4^2- --> no reaction

    If there is no precipitate when SO4^2-, added, there is no Ba^2+ present.

    Mn2+ + 2OH- --> Mn(OH)2(s)

    Since a reaction occurred with OH-, then Mn2+ must be present.

    • Log in to reply to the answers
Still have questions? Get answers by asking now.