Can someone check my answers? a. Ba2+, Mn2+ are present b. Mn2+ is present c. Mn2+ is present?
- hcbiochemLv 76 months agoFavorite Answer
So, your final answer would be that Mn2+ is the only one of these ions present in the solution. For each part, it would be better to say:
a. Hg22+ is not present
b. Ba2+ is not present
c. Mn2+ is present
- pisgahchemistLv 76 months ago
BaCl2 and MnCl2 are both soluble.
MnSO4 is soluble.
Hg2Cl2(s), Hg2SO4(s), and BaSO4(s) are insoluble
Hg(s) and HgO(s) form where one would expect Hg2(OH)2
Ba(OH)2(s) is slightly soluble, a precipitate will depend on the ion concentration
Mn(OH)2(s) is insoluble
Hg2^2+ + 2Cl- --> Hg2Cl2(s)
Ba2+ + Cl- --> no reaction
Mn2+ + Cl- --> no reaction
If there is no precipitate when Cl- added, there is no Hg2^2+ present.
Ba2+ + SO4^2- --> BaSO4(s)
Mn2+ + SO4^2- --> no reaction
If there is no precipitate when SO4^2-, added, there is no Ba^2+ present.
Mn2+ + 2OH- --> Mn(OH)2(s)
Since a reaction occurred with OH-, then Mn2+ must be present.