Simplify this maths problem?
I tried it and got 81/y^3 (0.04y^8)
What have I done wrong?
- ComoLv 73 months ago
( 18/y^4 ) x (y^8/25)
( 18/25 ) y^4
- 3 months ago
y8/y⁴ (81/25 ) = y ^(8-4) * 81/25
- JOHNLv 73 months ago
- sepiaLv 73 months ago
(-3/y)^4 (1/5 y^4)^2
= 81y^8 / (25 y^4)
= 81y^4 / 25
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- Jim MoorLv 73 months ago
81/y^4 (0.04y^8) is ok as far as it goes, but it could go further
81/y^4 * y^8 / 25
- PinkgreenLv 73 months ago
- KrishnamurthyLv 73 months ago
- llafferLv 73 months ago
First, keep fractions as fractions.
Then your y's can be combined from the first factor and the second factor.
You started correctly, but needed to finish things up.
- LônLv 73 months ago
Do each separately first....
(81/y^4) x (y^8/25) ......now multiply
81y^8 / 25y^4