A ball is thrown horizontally from a 18 m -high building with a speed of 2.0 m/s .?

How far from the base of the building does the ball hit the ground?

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  • 2 months ago

    y(t) = ½at² +v₀t + h₀. <<<< memorize this. it's used extensively!!!

    y is the distance

    a is the acceleration

    t is time and must agree with the time units of the other factors

    v₀ is the initial velocity, 'from rest' means v₀ = 0

    h₀ is initial height or position

    'a' s Earth Standard Gravity in most projectile flights (but not always!!!)

    "Standard gravity" is, by definition, 9.80665 m/s² (about 32.1740 ft/s²).

    y(t) = ½at² +v₀t + h₀ <<< sub in your values

    0 = ½ * -9.80665* t² +(0)t + 18

    ½ * 9.80665* t² = 18

    9.80665* t² = 36

    t² = 3.670978366720542

    t = 1.915979740686352 sec

    Sigfigs: round to 2 digits

    t = 1.9 s

  • Anonymous
    2 months ago

    How long does the ball take to fall to the ground?

    18m = 1/2 * 9.81 m/sec^2 * time^2

    horizontal distance = time * 2 m/sec.

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