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# What is the position at 1 s? Answer in units of m.Velocity at 1 sec is -11?

Consider the acceleration of a particle along a

straight line with an initial position of −1 m

and an initial velocity of −6 m/s.

What is the position at 1s?

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- NCSLv 78 months ago
If the acceleration is uniform, then it is

a = Δv / Δt = (-11 - 6)m/s / 1s = -5 m/s²

then

x = x₀ + v₀*t + ½at² = -1m - 6m/s*1s - ½*5m/s²*(1s)² = -9.5 m

which might have to be rounded to -10 m

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- Anonymous8 months ago
V = Vo+a*t = -6-5*1 = -11 m/sec

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