Calculate the concentration of unknown protein in mg/mL. Molecular weight=66300, molar extinction at 280=43700M-1cm-1, abs at 280nm=0.296?

1 Answer

  • 5 months ago

    Absorbance = extinction X concentration X path length

    0.296 = 43700 X c X 1 cm

    c = 6.67X10^-6 mol/L

    6.67X10^-6 mol/L X (66300 g/mol) X 1000 mg/g X (1 L/1000 mL) = 0.449 mg/mL

    • Log in to reply to the answers
Still have questions? Get answers by asking now.