# Calculate the concentration of unknown protein in mg/mL. Molecular weight=66300, molar extinction at 280=43700M-1cm-1, abs at 280nm=0.296?

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- hcbiochemLv 75 months ago
Absorbance = extinction X concentration X path length

0.296 = 43700 X c X 1 cm

c = 6.67X10^-6 mol/L

6.67X10^-6 mol/L X (66300 g/mol) X 1000 mg/g X (1 L/1000 mL) = 0.449 mg/mL

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