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A student dissolve 3.65g of hydrogen chloride gas, HCl into the water to prepare 1.0dm^3 of acid solution.calculate the volume of barium hydroxide solution,Ba(OH)2 0.10mol dm^-3 needed to neutralise 25.0cm^3 of acid solution completely.
Answer given is 12.5cm^3
- 8 months agoFavourite answer
Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O balanced equation
moles HCl = 3.65 g HCl x 1 mol/36.5 g = 0.1 mol
0.1 mol HCl/L x 0.025 L = 0.0025 moles HCl used in the reaction
moles Ba(OH)2 needed to neutralize this = 0.0025 mol HCl x 1 mol Ba(OH)2/2 mol HCl = 0.00125 mol Ba(OH)2 needed
Volume of 0.1 M Ba(OH)2 needed: 0.1 mol/L (x L) = 0.00125 moles and x = 0.0125 L = 12.5 ml = 12.5 cm^3