Math for business question?

A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3237 tickets overall. It has sold 183 more​ $20 tickets than​ $10 tickets. The total sales are ​$60,750. How many tickets of each kind have been​ sold?

How many $10 tickets?

How many $20 tickets?

How many $30 tickets?

3 Answers

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  • 2 months ago

    x = # $10 tickets

    y = # $20 tickets

    z = # $30 tickets

    x + y + z = 3237

    y - x = 183 or x = y - 183

    so 2y + z = 3420 ...... add these two equations together

    10*x + 20*y + 30*z = 60750 .......... the dollar amounts

    ==> 10(y - 183) +20y + 30z = 60750

    ==> 30y + 30z = 60750 + 1830

    ==> y + z = 2025 + 61

    ==> y + z = 2086

    ==> y = 3420 - 2086 = 1334

    hence z = 2086 -1334 = 752

    and x = 1334 - 183 = 1151

    so 1151 $10 tickets

    and 1334 $20 tickets

    and 752 $30 tickets

    total 3237 tickets.... (check)

  • KaleyK
    Lv 7
    2 months ago

    $10 x 1,151 = $11,510

    $20 x 1,334 = $26,680

    $30 x 752 = $22,560

    1,151 + 1,334 + 752 = 3,237 tickets sold

    $11,510 + $26,680 +$22,560 = $60,750

  • Lujk
    Lv 4
    2 months ago

    10x+20y+30z = 60750

    x+y+z = 3237

    y = x + 183

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