Max asked in Science & MathematicsPhysics · 7 months ago

physics question #4?

When you drop a 0.42 kg apple, Earth exerts

a force on it that accelerates it at 9.8 m/s


toward the earth’s surface. According to Newton’s third law, the apple must exert an equal

but opposite force on Earth.

If the mass of the earth 5.98 × 1024 kg, what

is the magnitude of the earth’s acceleration

toward the apple?

Answer in units of m/s



1 Answer

  • oubaas
    Lv 7
    7 months ago

    accel. a = F/me = 0.42*9.806*10^-24/5.98 = 6.89*10^-25 m/sec^2

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