# math helppp?

Factor 3a^4b - 3ab^4

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- DavidLv 410 months ago
Pull out the obvious common factor of 3ab

3ab(a³ - b³)

A potentially useful rule is that any polynomial of the form a^n - b^n has a factor a - b.

Then factoring out by comparing coefficients, we get

3ab(a³ - b³) = 3ab(a - b)(a² + ab + b²)

We can't factor any further without complex numbers

With complex numbers, the result is:

3/4ab(a - b)(2b + a(1 - i√3))(2b + a(1 + i√3))

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