In the combination of 3 Ω resistors shown in the diagram?
a) What is the resistance of each of the two parallel combinations?
b) What is the total equivalent resistance between points A and B?
c) If there is a voltage difference of 15 V between points A and B, what is the
current flowing through the entire combination?
d) What is the current flowing through each of the resistors in the three-resistor
- WhomeLv 77 months ago
Two parallel resistors
Re = 1 / (1/3 + 1/3) = 1.5 Ω
Three parallel resistors
Re = 1 / (1/3 + 1/3 + 1/3) = 1.0 Ω
Total equivelent resistance
Re = 1.5 + 3 + 1.0 = 5.5 Ω
Ι = 15 / 5.5 = 2.727272... = 2.7 Amps
Through each of the three parallel resisters will be one third of the total
I = 2.727 / 3 = 0.90909... = 0.91 Amps
- Robert JLv 77 months ago
Work out each parallel network first, then you have a simple three-value series network.
From A to B:
two 3R in parallel = 1.5R,
then three 3R in parallel = 1R.
1.5 + 3 + 1 = 5.5R
Current at 15V = 15 / 5.5 = 2.727272' Amps.
With three equal resistors in parallel, the current is divided equally in three so that value divided by three.