Calculate the mole of compounds in 15.8g of Fe(ClO4)3?
- Roger the MoleLv 74 weeks ago
(15.8 g Fe(ClO4)3) / (354.1968 g Fe(ClO4)3/mol) = 0.0446 mol Fe(ClO4)3
- JohnLv 74 weeks ago
First you need to calculate the molar weight of your compound, Iron(III) Perchlorate. Divide 15.8 g by the molar weight of your compound and there's your answer. Molar weight of elements in your compound:
Fe 55.84 g/mol
Cl 35.45 g/mol
O 16 g/mol