Lion asked in Science & MathematicsChemistry · 10 months ago

An athlete has a large lung capacity, 6.8 L?

An athlete has a large lung capacity, 6.8 L. Assuming air to be an ideal gas, how many molecules of air are in the athlete's lungs when the air temperature in the lungs is 37 ∘C under normal atmospheric pressure?

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  • 10 months ago
    Favourite answer

    n = PV / RT = (1.00 atm) x (6.8 L) / ((0.082057366 L atm/K mol) x (37 + 273) K) =

    0.26732 moles

    (0.26732 moles) x (6.022 x 10^23 molecules/mole) = 1.6 x 10^23 molecules

  • Dylan
    Lv 6
    10 months ago

    PV = nRT

    n = PV/(RT)

     = (6.8*101.325)/(8.314*(273.15+37))

     = 0.267 mols

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