# How much work must you do to push a 13 kg block of steel across a steel table (μk=0.6) at a steady speed of 1.1 m/s for 8.0 s ?

How much work must you do to push a 13 kg block of steel across a steel table (μk=0.6) at a steady speed of 1.1 m/s for 8.0 s?

b.)What is your power output while doing so?

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- RealProLv 78 months agoFavourite answer
Normal force = weight = mg

Friction = µmg

If constant speed then push force = friction

Work = µmg * (1.1 m/s) * (8.0 s)

Round your answer to 2 significant digits and not 3.

Power = work / time. So that's speed * force.

1.1 * 0.6 * 13 * 9.8 watts

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- Anonymous8 months ago
you need to do your own pearson homework.

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