# 1.00 mole of Al(NO3)3 contains how many oxygen atoms? The molar mass of Al(NO3)3 is 213.0 g/mol.?

### 4 Answers

Relevance

- az_lenderLv 71 month ago
1.00 mole of anything contains

6.022 x 10^23 molecules.

Each molecule of Al(NO3)3 contains 9 oxygen atoms.

So 1.00 mole of Al(NO3)3 contains

5.42 x 10^24 oxygen atoms.

- Log in to reply to the answers

- martinLv 71 month ago
One mole of Al(NO3)3 contains 9 oxygen atoms, because Al(NO3) contains 3, and it's multiplied by 3.

- Log in to reply to the answers

- pisgahchemistLv 71 month ago
How many O atoms.....

Simply set up the conversion factors used in the unit-factor method.

1.00 mol Al(NO3)3 x (9 mol O / 1 mol Al(NO3)3) x (6.022x10^23 atoms O / 1 mol O) = 5.42x10^24 atoms O

In the unit-factor method the units you don't want will cancel out, leaving the units you do want.

- Log in to reply to the answers

- Bobby_ThinLv 71 month ago
1.00 mole of Al(NO3)3 contains 9.0 mole of O atoms

number of atoms = 9* 6.02*10^23 = 5.42* 10^24 atoms of Oxygen

- Log in to reply to the answers

Still have questions? Get answers by asking now.