Anonymous
Anonymous asked in Science & MathematicsPhysics · 1 month ago

Extremely Basic Physics Question?

At time t=2s, an object moves to the right at the velocity of 3 m/s. At time t=3s, the object moves to the left at a velocity of 4 m/s. What is the average acceleration of the object? I know that the answer is 1 m/s^2 to the left but can someone please explain? Thanks a ton :)

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  • 1 month ago

    Acceleration = CHANGE in velocity / CHANGE in time

    = (v2-v1)/(t2-t1) = ( (-4) - (+3) ) / (3-2) = -7 / 1 = -7 m/s^2

    NOT -1 m/s^2  What you KNOW is wrong.

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  • 1 month ago

    In just 1 second, the velocity changed from + 3 m/s to - 4 m/s. That's a change of -7 m/s per second. Also written as -7 m/s^2.

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  • 1 month ago

    take to the right as +, to the left as –

    acceleration = ΔV/Δt = (– 4 – 3) / (3 – 2) = –7/1 = –7 m/s²

    so the average acceleration is 7 m/s² to the left

    no, 1 m/s² is not correct.

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