Extremely Basic Physics Question?
At time t=2s, an object moves to the right at the velocity of 3 m/s. At time t=3s, the object moves to the left at a velocity of 4 m/s. What is the average acceleration of the object? I know that the answer is 1 m/s^2 to the left but can someone please explain? Thanks a ton :)
- Andrew SmithLv 71 month ago
Acceleration = CHANGE in velocity / CHANGE in time
= (v2-v1)/(t2-t1) = ( (-4) - (+3) ) / (3-2) = -7 / 1 = -7 m/s^2
NOT -1 m/s^2 What you KNOW is wrong.
- MorningfoxLv 71 month ago
In just 1 second, the velocity changed from + 3 m/s to - 4 m/s. That's a change of -7 m/s per second. Also written as -7 m/s^2.
- billrussell42Lv 71 month ago
take to the right as +, to the left as –
acceleration = ΔV/Δt = (– 4 – 3) / (3 – 2) = –7/1 = –7 m/s²
so the average acceleration is 7 m/s² to the left
no, 1 m/s² is not correct.