A football punter accelerates a 0.59 kg football from rest to a speed of 10 m/s in 0.19 s.?
A football punter accelerates a 0.59 kg football from rest to a speed of 10 m/s in 0.19 s.
What constant force does the punter exert
on the ball?
Answer in units of N.
- MyRankLv 68 months ago
Mass (m) = 0.59kg
Time (t) = 0.19sec
Speed (v) = 10m/sec
Force (F) = ?
We know that:-
Force (F) = Mass (m) x Acceleration (a)
Force (F) = 0.59kg x speed (v) / Time (t) = 0.59kg x 10m/sec / 0.19sec Force (F) = 0.59kg x 52.63m/sec² = 31.05kg.m/sec² ∴ Force (F) = 31.05NSource(s): https://myrank.co.in/
- 8 months ago
use the newton second law of motion
- Anonymous8 months ago
F = m*a = m*ΔV/Δt = 0.59*10*100/19 = 31 N