# A football punter accelerates a 0.59 kg football from rest to a speed of 10 m/s in 0.19 s.?

A football punter accelerates a 0.59 kg football from rest to a speed of 10 m/s in 0.19 s.

What constant force does the punter exert

on the ball?

Answer in units of N.

### 3 Answers

Relevance

- MyRankLv 68 months ago
Given,

Mass (m) = 0.59kg

Time (t) = 0.19sec

Speed (v) = 10m/sec

Force (F) = ?

We know that:-

Force (F) = Mass (m) x Acceleration (a)

Force (F) = 0.59kg x speed (v) / Time (t) = 0.59kg x 10m/sec / 0.19sec Force (F) = 0.59kg x 52.63m/sec² = 31.05kg.m/sec² ∴ Force (F) = 31.05N

Source(s): https://myrank.co.in/ - 8 months ago
use the newton second law of motion

F=ma

m=0.50kg

a=10/0.19

a=52.63

F=0.50*52.63

F=26.35N

- Anonymous8 months ago
F = m*a = m*ΔV/Δt = 0.59*10*100/19 = 31 N

Still have questions? Get answers by asking now.