# What is the molar mass of a 1.9g sample of gas exerting 3.5 atm of pressure at 575k in a 12.5 L container?

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- Old Science GuyLv 71 month agoFavorite Answer
m/V R T = M P

1.9/12.5 (0.08206)(575) = M (3.5)

M = 2.05 g/mol

sounds like hydrogen

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- Roger the MoleLv 71 month ago
n / V = P / RT = (3.5 atm) / ((0.082057366 L atm/K mol) x (575 K)) = 0.074179 mol/L

(1.9 g) / (12.5 L) / (0.074179 mol/L) = 2.049 mol/L = 2.0 mol/L

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- az_lenderLv 71 month ago
n = pV/(RT), and

the molar mass is (1.9g)/n.

Where R = 0.08206 L*atm/(mol*K)

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