Anonymous
Anonymous asked in Science & MathematicsPhysics · 4 weeks ago

Physics help?

A car with mass 1360 kg crashes into a wall.

The car’s velocity immediately before the collision was 12.4 m/s and the bumper is compressed like a spring with spring constant

1.14 × 107 N/m.

What is the maximum deformation of the

bumper for this collision?

Answer in units of m.

2 Answers

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  • Whome
    Lv 7
    4 weeks ago
    Favorite Answer

    ½kx² = ½mv²

    x = √(mv²/k) = √(1360(12.4²)/1.14 × 10^7) = 0.1354...m or about 13.5 cm

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  • oubaas
    Lv 7
    4 weeks ago

    m*V^2 = k*x^2

    x = √m*V^2 / k = √1.36*12.4^2/(1.14*10^4) = 0.135 m (13.5 cm)

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