Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

math problem 5?

The remainder when the polynomial P(x) is divided by x−1 and x+1 are is 4 and 8, respectively. If the remainder when P(x) is divided by x^2−1 is R(x), determine the value of R(6).

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  • 4 weeks ago

    x^2−1 is quadratic so R(x) is linear.

    R(x) passes through (1,4) and (-1,8) so R(x) = -2x + 6, and R(6) = -6

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  • Ian H
    Lv 7
    1 month ago

    The remainders when the polynomial P(x) is divided by x − 1 and x + 1  

    are 4 and 8, respectively. If the remainder when P(x) is divided by x^2 − 1 is R(x), determine the value of R(6) 

     

    Suppose P = x^2 – 1 + kx + c 

    When the polynomial P(x) is divided by the linear divisor (x - 1) the remainder,  

    is equal to the value of the polynomial evaluated at x = 1. 

    1 – 1 + k + c = c + k = 4 

     

    When the polynomial P(x) is divided by the linear divisor (x + 1) the remainder,  

    is equal to the value of the polynomial evaluated at x = -1. 

    1 – 1 - k + c = c – k = 8 

    c = 6, k = -2 

    P = x^2 – 2x + 5 

    P = x^2 – 1 + (6 – 2x) 

    P(x) divided by x^2−1 = 1 + (6 – 2x)/(x^2 – 1) 

    R(x) = 6 – 2x 

    R(6) = -6 

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