Titration of 30.00 mL of a 0.0800 M acetic acid solution with 0.0850 M KOH. How many mmol of acetate are present at the equivalence point?

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  • 2 months ago

    acetic acid + KOH = potassium acetate + H2O  [balanced as written]

    (30.00 mL) x ( 0.0800 M acetic acid) x (1 mol acetate / 1 mol acetic acid) =

    2.4 mmol acetate

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  • 2 months ago

    2......................

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