Titration of 30mL of 0.08M acetic acid solution with 0.0850M KOH. What's the analytical concentration of acetate ions at equivalence point?
- Roger the MoleLv 72 months ago
Supposing the potassium acetate ionizes completely:
(30 mL) x (0.08M acetic acid) x (1 mol acetate / 1 mol acetic acid) / (58 mL) =
0.041 M acetate
Still have questions? Get answers by asking now.