# find and classify the discontinuities of x+5/x-6?

please explain how to do it

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- PuzzlingLv 72 months ago
I'm assuming you actually meant to write:

(x+5)/(x-6)

There is a discontinuity in the function when the denominator is zero.

x - 6 = 0

x = 6

So you have a vertical asymptote (and hence a discontinuity) at x=6.

If they were asking about asymptotes, you also have a *horizontal* asymptote at y=1.

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- Anonymous2 months ago
You need to look for the lowest common denominator.

- DylanLv 62 months agoReport
This guy is a joke.

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- Anonymous2 months ago
you find where the denominator is 0

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