find and classify the discontinuities of x+5/x-6?

please explain how to do it

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  • 2 months ago

    I'm assuming you actually meant to write:

    (x+5)/(x-6)

    There is a discontinuity in the function when the denominator is zero.

    x - 6 = 0

    x = 6

    So you have a vertical asymptote (and hence a discontinuity) at x=6.

    If they were asking about asymptotes, you also have a *horizontal* asymptote at y=1.

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  • Anonymous
    2 months ago

    You need to look for the lowest common denominator.

    • Dylan
      Lv 6
      2 months agoReport

      This guy is a joke.

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  • Anonymous
    2 months ago

    you find where the denominator is 0

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