# find and classify the discontinuities of x+5/x-6?

please explain how to do it

Relevance
• 2 months ago

I'm assuming you actually meant to write:

(x+5)/(x-6)

There is a discontinuity in the function when the denominator is zero.

x - 6 = 0

x = 6

So you have a vertical asymptote (and hence a discontinuity) at x=6.

If they were asking about asymptotes, you also have a *horizontal* asymptote at y=1.

• Anonymous
2 months ago

You need to look for the lowest common denominator.

• Dylan
Lv 6
2 months agoReport

This guy is a joke.