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Calculate the quantity of heat needed to turn 200 g of 100∘C water to steam at the same temperature. The heat of vaporization for water Lv is 540 cal/g.

Express your answer to two significant figures and include the appropriate units.

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  • Whome
    Lv 7
    2 months ago
    Favourite answer

    200 g(540 cal/g) = 108000 cal = 1.1 x 10^5 cal

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  • 2 months ago

    By Q = ML

    =>Q = 200 x 540 

    =>Q = 108000 cal OR 108 kcal

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  • Anonymous
    2 months ago

    mass * heat of vaporization

     

    Doesn't get much easier than that.

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