Euro asked in Science & MathematicsPhysics · 4 months ago

How is this not an A dim chord?

Diminished chords are built with a root, minor 3rd and a diminished 5th. Since there's no B#, do I play a C instead of a Cb?

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  • 4 months ago

    The root form of Adim is  A, C,  D# and F# (you just move up a minor-third to get to the next note).

    There are 4 notes because it also includes the double-diminished (double-flattened) 7th of the scale.

    (Note, the chords Adim, Cdim, D#dim and F#dim, for example, all have the same notes, so are really the same chord.)

    In your diagram, you have only 3 notes. There are *many* chords which contain these 3 notes -  as shown on the right of the diagram.

    The chord you show (A, D#, B) is not Adim, but if you raise the B to a C, you get A dim.

    Hope that helps.  (By the way, it’s not a Physics question!)

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