What volume of 0.10 M hydrochloric acid would be required to react with 1.7 g of silver nitrate?

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  • 4 months ago

    AgNO3 + HCl → AgCl + HNO3    [balanced as written]

    (1.7 g AgNO3) / (169.87323 g AgNO3/mol) x (1 mol HCl / 1 mol AgNO3) / 

    (0.10 mol/L HCl) = 0.10 L

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