What volume of 0.10 M hydrochloric acid would be required to react with 1.7 g of silver nitrate?
- Roger the MoleLv 74 months ago
AgNO3 + HCl → AgCl + HNO3 [balanced as written]
(1.7 g AgNO3) / (169.87323 g AgNO3/mol) x (1 mol HCl / 1 mol AgNO3) /
(0.10 mol/L HCl) = 0.10 L
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