Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

given angle DBC = 20 degrees, AB=25 and DC=7, calculate the following measurements.

angle A=

area of triangle ABC= Relevance

tan ∠DBC = DC/BD

tan 20° = 7/BD

BD = 7/tan 20°

BD ≈ 19

sin ∠A = BD / AB

∠A = arcsin (19/25)

∠A = 49.5°

AD = √(AB² - BD²) = √(25² - 19²) ≈ 16

Area ΔABC = ½(AC * BD) = ½((AD + DC) * BD) = ½((16 + 7) * 19) = 218.5

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• given angle DBC = 20 degrees, AB = 25, and DC = 7, calculate the following measurements.

angle A = 53.13 degrees

area of triangle ABC = 220 units^2

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•  Given angle DBC = 20°, AB = 25, and DC = 7,

calculate the following measurements:

Since ABD is a right triangle in which the hypotenuse measures 25

the other sides of the triangle are 15 and 20

Because it is a right triangle one angle is obviously 90°.

The other two are approximately 36.87° and 53.13°.

Angle A = 53.13°

Length of AC = 22

Area of triangle ABC = 220 units^2

Angle C = 70°

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