I need to know how to set up 4w(2w+1)=2w+1 solve by factoring ?

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  • 1 month ago

    First, don't follow anyone's advice if they say you should divide both sides by 2w+1. That expression might be zero and you don't want to divide by zero. In fact, if you do follow those steps, you lose one of the possible solutions.

    Instead, *subtract* 2w+1 from both sides. This will get everything together on one side and leave you with a zero on the other side.

    4w(2w + 1) - (2w + 1) = 0

    Now think of the second part as -1(2w + 1):

    4w(2w + 1) - 1(2w + 1) = 0

    Then factor out the common 2w + 1:

    (4w - 1)(2w + 1) = 0

    The zero product rule say, if you have ab=0, then a=0 or b=0:

    4w - 1 = 0

    4w = 1

    w = 1/4

    or

    2w + 1 = 0

    2w = -1

    w = -1/2

    Answers:

    w = -1/2 or w = 1/4

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  • 1 month ago

    4w(2w+1)=2w+1

    =>

    8w^2+4w=2w+1

    =>

    8w^2+4w-2w-1=0

    =>

    4w(2w+1)-(2w+1)=0

    =>

    (2w+1)(4W-1)=0

    =>

    w=-1/2 or w=1/4

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  • RR
    Lv 7
    1 month ago

    4w(2w+1)=2w+1

    8w² + 4w = 2w + 1

    8w² + 2w - 1 = 0

    (4x - 1)(2x + 1) = 0

    4x = 1

    x = 1/4

    or

    2x = -1

    x = - 1/2

    • ...Show all comments
    • Puzzling
      Lv 7
      1 month agoReport

      Really? They started out with w and just accidentally switched to x. I think someone can make the mental switch to realize it's the same answer if you just use w.

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  • 1 month ago

    4w(2w+1)=2w+1

    8w^2 + 4w = 2w + 1

    8w^2 + 4w - 2w - 1 = 0

    8w^2 + 2w - 1 = 0

    (4w - 1)(2w  + 1) = 0

    4w - 1 =0, 2w + 1 = 0

    w = 1/4 , w = - 1/2

    roots are: w = 1/4 or - 1/2... Answer//

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  • 1 month ago

    4w.(2w + 1) = 2w + 1

    4w.(2w + 1) = (2w + 1)

    4w.(2w + 1) - (2w + 1) = 0

    [4w * (2w + 1) - [1 * (2w + 1)] = 0

    (4w  - 1).(2w + 1) = 0 → one of these 2 factors must be zero

    First case: (4w - 1) = 0 → 4w - 1 = 0 → 4w = 1 → w = 1/4

    Second case: (2w + 1) = 0 → 2w + 1 = 0 → 2w = - 1 → w = - 1/2

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  • 1 month ago

    For clarity... . At the level of [4w*(2w+1) - (2w+1)] = 0 you factor out  the (2w + 1) which gives (2w+1) * (4w*1 - 1) and then carry on.

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  • 1 month ago

    Subtract 2w+1 from both sides

    4w(2w+1) - (2w+1) = 0

    Use the distributive property

    (4w-1) (2w+1) = 0

    Use the zero product property

    4w - 1 = 0 or 2w+1 = 0

    w = 1/4 or w = -1/2

    • Puzzling
      Lv 7
      1 month agoReport

      Exactly!

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  • 1 month ago

    The answer is w = 1/4 and I can see it without writing it down.

    Hint:  Divide both sides of the = by (2w + 1)

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    • Puzzling
      Lv 7
      1 month agoReport

      If w = -1/2, you are dividing both sides by 0. And that's also why you lost one of the solutions of w = -1/2.

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  • 1 month ago

    it is already factored. 

    4w(2w+1) = 2w+1

    8w² + 4w = 2w + 1

    8w² + 2w – 1 = 0

    (4w – 1)(2w + 1) = 0

    w = 1/4, –1/2

    check

    4(1/4)(2(1/4)+1) = 2(1/4)+1

    (2(1/4)+1) = 2(1/4)+1

    ok

    4(–1/2)(2(–1/2)+1) = 2(–1/2)+1

    4(–1/2)(2(–1/2)+1) = 2(–1/2)+1

    0 = 0

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  • 1 month ago

    4w(2w + 1) = (2w + 1)

    4w = (2w + 1)/(2w + 1) = 1

    w = 1/4 = 0.25

    • ...Show all comments
    • Puzzling
      Lv 7
      1 month agoReport

      If w = -1/2, you are dividing by 0. In fact, in doing so, you lose the other solution of w = -1/2.

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