What is the pOH of a 9.50 x 10-6 M KOH solution? (Hint: this is a basic solution – concentration is of OH)?

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  • 5 months ago

    pOH = -log [OH^-]

    KOH is a strong base, which means it ionizes 100% in solution.

    pOH = -log 9.50 x 10^-6

    pOH = 5.022

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