What is the pOH of a 9.50 x 10-6 M KOH solution? (Hint: this is a basic solution – concentration is of OH)?
- ChemTeamLv 75 months ago
pOH = -log [OH^-]
KOH is a strong base, which means it ionizes 100% in solution.
pOH = -log 9.50 x 10^-6
pOH = 5.022
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