Suppose a container has an initial volume of 11.6 L and the gas contained within is exerting a pressure 824 Pa. If we increase the volume of the container to 14.5 L, what will the pressure exerted by the gas be in larger volume? (Temperature is being held constant.)
- AshLv 75 months ago
At constant temperature,
P₁V₁ = P₂V₂
P₂ = P₁V₁ /V₂ = (824 Pa)(11.6 L)/(14.5 L) = 659 Pa
- Anonymous5 months ago
Did the answers to your earlier question help at all: https://ph.answers.yahoo.com/question/index?qid=20...