Identify the substance that absorbs 189 J of energy when a mass of 15 grams undergoes a temperature increase of 6 degrees Celsius.?

What is the specific heat? Show your work in the space provided.

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  • 1 month ago

    Q = mcDeltaT 

    When 

    Q = 189 J 

    m = 15 g  

    c to be found ( the specific heat of the substance) 

    DeltaT = 6K 

    Hence 

    c = Q/(mDeltaT) 

    c = 189 J / (15g x 6K)

    c = 2.1 J/gK

    Look up a table of specific heats ( in Wikipedia) 

    This could be liquid methanol (methyl alcohol) at 2.14 J/gK

  • 1 month ago

    (189 J) / (15 g) / (6°C) = 2.10 J / g·°C

    The substance with specific heat like that is ice.

  • 1 month ago

    you have asked about 4-5 identical questions with just the numbers changed. Don't you think you could work out one yourself?

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