You take 15.0 mL of a 0.1250 M Cu(NH3)2+ solution and add 10.0 mL of water to it. What is the concentration of the new solution?
- Roger the MoleLv 71 month ago
Supposing additive volumes:
(0.1250 M) x (15.0 mL) / (15.0 mL + 10.0 mL) = 0.0750 M
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