Calculate the concentration of an aqueous KCl solution if 431 mL of the solution gives 55.9 g of AgCl when treated with excess AgNO3.?
The reaction's equation is KCl( aq) + AgNO 3( aq) ----> AgCl( s) + KNO 3( aq).
- jacob sLv 74 weeks ago
KCl (aq) + AgNO3 (aq) -> AgCl (s) + KNO3 (aq)
Moles of AgCl produced = weight/molecular weight = 55.9/143.3 = 0.390 moles
From the stiochiometry of the reaction, the molar ratio between KCl and AgCl is 1:1.
So, the initial KCl = 0.390 moles ( AgNO3 in excess , we can neglect)
Initial concentration of KCl = (number of moles/volume in mL) * 1000 = (0.390/431)*1000 = 0.91 M