Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

If (6.31)^m = (3.02)^n, what is the value of m/n?

A)-0.32

B)0.32

C)0.48

D)0.60

E)1.67

Would be great if someone helped.Thanks:)

7 Answers

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  • Favourite answer

    6.31^m = 3.02^n

    m * ln(6.31) = n * ln(3.02)

    m/n = ln(3.02) / ln(6.31)

    m/n = 0.5999866597529120191759266929277......

  • Philip
    Lv 6
    1 month ago

    For (6.31)^m = (3.02)^n, m*ln(6.31) = n*ln(3.02). Then (m/n) = ln(3.02)/ln(6.31) =

    0.5999866598 = 0.60 rounded to 2 decimal places. Option D) shows correct answer.

  • 1 month ago

    (6.31)^m = (3.02)^n

    mln(6.31) = n(ln(3.02)

      

    m/n = ln(3.02)/ln(6.31)

    m/n = 0.5999 or 0.60 answer//

  • 1 month ago

     If (6.31)^m = (3.02)^n, what is the value of m/n?

     m log 6.31 = n log 3.02

     m/n = log 3.02/log 6.31 = 0.599987...

     Answer choice:

     D) 0.60

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  • Ian H
    Lv 7
    1 month ago

    m/n = log(3.02)/log(6.31)  = 0.599986659753... ~ 0.6 so, D.

  • rotchm
    Lv 7
    1 month ago

    Hint: take the log each side.

  • 1 month ago

    m log(6.31) = n log(3.02) logs to base ten, not the natural logs.

    So:

    m/n = log(3.02)/log(6.31) = 0.600 ANS D.

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