Anonymous
Anonymous asked in Science & MathematicsMathematics · 1 month ago

# If (6.31)^m = (3.02)^n, what is the value of m/n?

A)-0.32

B)0.32

C)0.48

D)0.60

E)1.67

Would be great if someone helped.Thanks:)

Relevance
• 1 month ago

6.31^m = 3.02^n

m * ln(6.31) = n * ln(3.02)

m/n = ln(3.02) / ln(6.31)

m/n = 0.5999866597529120191759266929277......

• Philip
Lv 6
1 month ago

For (6.31)^m = (3.02)^n, m*ln(6.31) = n*ln(3.02). Then (m/n) = ln(3.02)/ln(6.31) =

0.5999866598 = 0.60 rounded to 2 decimal places. Option D) shows correct answer.

• 1 month ago

(6.31)^m = (3.02)^n

mln(6.31) = n(ln(3.02)

m/n = ln(3.02)/ln(6.31)

m/n = 0.5999 or 0.60 answer//

• 1 month ago

If (6.31)^m = (3.02)^n, what is the value of m/n?

m log 6.31 = n log 3.02

m/n = log 3.02/log 6.31 = 0.599987...

D) 0.60

• Ian H
Lv 7
1 month ago

m/n = log(3.02)/log(6.31)  = 0.599986659753... ~ 0.6 so, D.

• rotchm
Lv 7
1 month ago

Hint: take the log each side.

• 1 month ago

m log(6.31) = n log(3.02) logs to base ten, not the natural logs.

So:

m/n = log(3.02)/log(6.31) = 0.600 ANS D.