5. 2.00 L of a gas is at 740.0 mmHg pressure. What is its volume at standard pressure? ?
- jacob sLv 73 weeks ago
at constant mole (n) and temperature
PV= constant(; . n,T,R are constant)
⇒ P1V1 = P2V2
P1= 740mmHg P2= 1.00 atm
V1= 2.00 L V2= ?
P1= 740/760 = 0.97 atm
⇒ V2 =P1V1/P2 = (0.97 atm)(2L)/(1atm)
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