# Hi, can i have some help with this? ?

If sinθ=3/5 and θ is in quadrant II, then

cos(θ)=

;

tan(θ)=

;

cot(θ)=

;

sec(θ)=

;

csc(θ)=

;

### 2 Answers

Relevance

- Engr. RonaldLv 71 month ago
from 2nd quadrant

cos(θ) = √(1 - sin^2(x))

cos(θ) = √(1 - (3/5)^2)

= √(16/25)

=- 4/5

tan(θ) = - 3/4

cot(θ) = - 4/3

sec(θ) = - 5/4

csc(θ) = 5/3

- ted sLv 71 month ago
so you have a { - 4 , 3 , 5 } reference triangle , use this to answer your query

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