Hi, can i have some help with this? ?

If sinθ=3/5 and θ is in quadrant II, then

cos(θ)=

 ;

tan(θ)=

 ;

cot(θ)=

 ;

sec(θ)=

 ;

csc(θ)=

 ;

2 Answers

Relevance
  • 1 month ago

    from 2nd quadrant

    cos(θ) = √(1 - sin^2(x))

    cos(θ) = √(1 - (3/5)^2)

       = √(16/25)

      =- 4/5

    tan(θ) = - 3/4

    cot(θ) = - 4/3

    sec(θ) = - 5/4

    csc(θ) = 5/3

  • ted s
    Lv 7
    1 month ago

    so you have a { - 4 , 3 , 5 } reference triangle , use this to answer your query

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