# How many grams of fluorine gas occupy 543.2 mL and expect 123456 Pa of pressure at 29.8 degrees Celsius?

### 1 Answer

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- jacob sLv 73 weeks ago
We know that the Ideal gas equation is PV =nRT

Where,P =Pressure exerted by the gas

v =volume

n= number of moles

R =Universal gas constant

T =Temperature in kelvin

The molar mass of F2 molecule is 37.99 g/mol

The temperature T =29.8 degree celsius =302.8 k

Volume =543.2 mL =0.5432 L

PRESSURE =123456 Pa =1.218 atm

So,according to PV =nRT ,(n =mass/molar mass)

PV =(mass/molar mass) * 0.0821atm*302.8 k

so,mass =(PV*Molar mass) / (0.0821*302.8 k )

=(1.218 atm *0.543L *37.99g/mol) / (0.0821 atm *302.8 k)

=1.01 g

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